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-16x^2+11x+6=0
a = -16; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·(-16)·6
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{505}}{2*-16}=\frac{-11-\sqrt{505}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{505}}{2*-16}=\frac{-11+\sqrt{505}}{-32} $
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